Hi, i am new to C and am still learning but i am trying to make a program that takes any input and turns it in to hex but i am having some problems with it because when i compile it and type in some text it only translates that first letter i am using %h to write my text to the screen so my print statment it like this.


can some one tell we what might be a better way of doing this.

perhaps the char buffer text is a single char and not char[256] say?

first of all: i don't know what %h does or if it even exists, but %x should normally give you hex output.

You must also understand that C doesn't really have a string type, you have to use arrays to store your stuff in.
printf("%s", string); will print out your entire string, but other operands won't do that.
%c, %d, %x will only work for one value.
So how do we solve this problem?
We can make a string and then go through all the values and print them


However, instead of using fget() to make an array, and then going through all our values one by one, we can also just change them at the input line:


this program will take a character at a time from the standard input and then print its hexadecimal value, until a newline is reached.

I hope this answers your question,
if it doesn't or you don't understand some things,

let me know,

gilbert

Thank you for your replys they helped a lot i under stand it now and i just typed in my code fast, sorry for the %h and not %x.

Cool little program gilbert0! I had three classes of C++ and never really did anything as cool as this little C program (*cough*, shitty state college). Thanks for sharing the knowledge mate.

I'm glad i could help, and if you really want to learn a lot of C, i recommend the book "Pointers on C" by Kennth A. Reek. It is a bit advanced and gets a bit hard some times, but you can really learn a lot from it.

phizer, you may want to consider changing schools . Although the school probably didn't think that translating strings into hex was very valuable.